factorize:
$12 m^{3} + 6 m^{2} - 6 m$

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Solution

We have,

$\Rightarrow 12 m^{3} + 6 m^{2} - 6 m$

$\Rightarrow 6 m (2 m^{2} + m - 1)$

$\Rightarrow 6 m (2 m^{2} + (2 m - m) - 1)$

$\Rightarrow 6 m (2 m^{2} + 2 m - m - 1)$

$\Rightarrow 6 m (2 m (m + 1) - 1 (m + 1))$

$\Rightarrow 6 m (m + 1) (2 m - 1)$
Hence, this is the answer.

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