Question

Factorize: $16a^2-8a+1$

Answer 1

The given polynomial is $16a^2-8a+1$

$16a^2-8a+1$

$=(4a{)}^2-2(4a\left)\right(1)+(1{)}^2$

$=(4a-1{)}^2$

$=(4a-1)(4a-1)$