Factorize $16 x^{6} - 8 x^{3} y^{3} + y^{6}$ ?

(4 x^{3} - y^{3})^{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

(4 x^{3} + y^{3})^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(4 x + y)^{6}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(16 x^{2} + y)^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $(4 x^{3} - y^{3})^{2}$
Given equation is $16 x^{6} - 8 x^{3} y^{3} + y^{6}$
The above equation be written as $(4 x^{3})^{2} - 2.4 x^{3} . y^{3} + (y^{3})^{2}$
The equation in the form of $(a - b)^{2} = a^{2} - 2 a b + b^{2}$
$a = 4 x^{3}, b = y^{3}$
We get the factor as $(4 x^{3} - y^{3})^{2}$

Suggest Corrections

Similar questions

Factorize $x^{6} + y^{6}$

\sqrt{1 - x^{6}} + \sqrt{1 - y^{6}} = a^{3} (x^{3} - y^{3})

\frac{d y}{d x} = \frac{x^{2}}{y^{2}} \sqrt{\frac{1 - y^{6}}{1 - x^{6}}}

x^{6} - y^{6}

Factors of $x^{6} - y^{6}$ is:

Join BYJU'S Learning Program