Factorize: $2 (2 x - 5 y) (3 x + 4 y) - 6 (2 x - 5 y) (x - y)$

2 (2 x - 5 y) (7 y)

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(2 x - 5 y) (7 y)

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2 (2 x - 5 y) (4 y + 3 x)

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2 (2 x + 5 y) (7 y)

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Solution

The correct option is A $2 (2 x - 5 y) (7 y)$
$\Rightarrow 2 (2 x - 5 y) (3 x + 4 y) - 6 (2 x - 5 y) (x - y)$

$Take out 2(2x - 5y) as common term$

$\Rightarrow 2 (2 x - 5 y) [(3 x + 4 y) - 3 (x - y)]$

$\Rightarrow 2 (2 x - 5 y) [3 x + 4 y - 3 x + 3 y]$

$\Rightarrow 2 (2 x - 5 y) [4 y + 3 y]$

$\Rightarrow 2 (2 x - 5 y) [7 y]$

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Similar questions

2 (2 x - 5 y) (3 x + 4 y) - 6 (2 x - 5 y) (x - y)

2 (2 x - 5 y) (3 x + 4 y) - 6 (2 x - 5 y) (x - y)

2(2x-5y) (3x+4y)-6(2x-5y) (x-y)

Factorise by taking out the common factors

Factorise:
$6 {(2 x - \frac{3}{x})}^{2} - 2 (2 x - \frac{3}{x}) - 20$

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