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Question

Factorize:
a2+4b24ab4c2

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Solution

Given: a2+4b24ab4c2
a2+4b24ab4c2
=(a2b)24c2
[x2+y22xy=(xy)2]
=(a2b)2(2c)2
=(a2b+2c)(a2b2c)
[x2y2=(x+y)(xy)]

Hence, a2+4b24ab4c2=(a2b+2c)(a2b2c).

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