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Byju's Answer
Standard VIII
Mathematics
Expansion of (x^2 - y^2)
Factorize:š2...
Question
Factorize:
a
2
+
4
b
2
−
4
a
b
−
4
c
2
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Solution
Given:
a
2
+
4
b
2
−
4
a
b
−
4
c
2
∴
a
2
+
4
b
2
−
4
a
b
−
4
c
2
=
(
a
−
2
b
)
2
−
4
c
2
[
∵
x
2
+
y
2
−
2
x
y
=
(
x
−
y
)
2
]
=
(
a
−
2
b
)
2
−
(
2
c
)
2
=
(
a
−
2
b
+
2
c
)
(
a
−
2
b
−
2
c
)
[
∵
x
2
−
y
2
=
(
x
+
y
)
(
x
−
y
)
]
Hence,
a
2
+
4
b
2
−
4
a
b
−
4
c
2
=
(
a
−
2
b
+
2
c
)
(
a
−
2
b
−
2
c
)
.
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Q.
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Q.
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Q.
Find the sum of
(viii) 𝑎𝑏𝑐+2𝑏𝑎+3𝑎𝑐, 4𝑐𝑎−4𝑎𝑏+2𝑏𝑐𝑎 and 2𝑎𝑏−3𝑎𝑏𝑐−6𝑎𝑐
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Expansion of (x^2 - y^2)
Standard VIII Mathematics
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