Factorize $2 {(x + y)}^{3} - 6 (x + y)$ by taking out the common factors

2 (x + y) (x^{2} + x y + y^{2} - 3)

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2 (x + y) (x^{3} + 2 x y + y^{2} - 5)

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2 (x + y) (x^{2} + 2 x y + y^{2} - 3)

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2 (x + y) (x^{3} + 2 x y + y^{2} - 3)

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Solution

The correct option is C $2 (x + y) (x^{2} + 2 x y + y^{2} - 3)$
$2 {(x + y)}^{3} - 6 (x + y)$
$= 2 (x + y) [(x + y)^{2} - (3)]$
$= 2 (x + y) (x^{2} + 2 x y + y^{2} - 3)$

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