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Question

Factorize :
22a3+8b327c3+182abc

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Solution

22a3+8b327c3+182abc

=(2)a3+(2b)3(3c)33(2a)(2b)(3c)

=(2a)3+(2b)3(3c)33(2a)(2b)(3c)

=(2a+2b3c)(2a2+4b2+9c242ab+6bc+32ac)

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