Factorize - 2-2a3-8b3-27c3-18-2abc

2√(2)a^3+8b^3 27c^3+18√(2)abc =(√(2))a^3+(2b)^3 (3c)^3 3(√(2)a)(2b)( 3c) =(√(2)a)^3+(2b)^3 (3c)^3 3(√(2)a)(2b)( 3c) =(√(2)a+2b 3c)(2a^2+4b^2 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Factorisation by Regrouping Terms

Factorize : ...

Question

Factorize :
$2 \sqrt{2} a^{3} + 8 b^{3} - 27 c^{3} + 18 \sqrt{2} a b c$

Open in App

Solution

Suggest Corrections

Similar questions

2 \sqrt{2} a^{3} + 8 b^{3} - 27 c^{3} + 18 \sqrt{2} a b c .

2 \sqrt{2} a^{3} + 8 b^{3} - 27 c^{3} + 18 \sqrt{2} a b c

Question 36
Factorise:
(i) $a^{3} - 8 b^{3} - 64 c^{3} - 24 a b c$

(ii) $2 \sqrt{2} a^{3} + 8 b^{3} - 27 c^{3} + 18 \sqrt{2} a b c$

Question 36
Factorise:
(i) $a^{3} - 8 b^{3} - 64 c^{3} - 24 a b c$

(ii) $2 \sqrt{2} a^{3} + 8 b^{3} - 27 c^{3} + 18 \sqrt{2} a b c$

{(a + 2 b - 3 c)}^{3} - a^{3} - 8 b^{3} + 27 c^{3}

Join BYJU'S Learning Program