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Question

Factorize:

2(x+y)29(x+y)5

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Solution

2(x+y)29(x+y)5
Let x+y=a, then
2a29a52×(5)=1010=10×19=10+1 =2a210a+a5=2a(a5)+1(a5)=(a5)(2a+1)=(x+y5)(2x+2y+1)


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