Factorize : $20 x^{2} + 3 x - 56$

(4 x - 7) (5 x + 8)

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(10 x - 4) (2 x + 14)

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(4 x + 7) (5 x - 8)

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(10 x + 7) (2 x + 8)

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Solution

The correct option is C $(4 x + 7) (5 x - 8)$
$A] 20 x^{2} + 3 x - 56$
$= 20 x^{2} + 35 x - 32 x - 56$
$= 5 (4 x^{2} + 7 x) - 8 (4 x + 7)$
$= 5 x (4 x + 7) - 8 (4 x + 7)$
$= (5 x - 8) (4 x + 7)$

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