20x2 45=54x2 9 #160; #160; #160; #160; #160; #160; #160; #160; #160; #160; #160; #160; #160; #160; #160; #160;=52x2 32 #160; ...

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Byju's Answer

Standard IX

Mathematics

Polynomials

Factorize:20 ...

Question

Factorize:
20x² − 45

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Solution

$20 x^{2} - 45 = 5 (4 x^{2} - 9) = 5 [{(2 x)}^{2} - {(3)}^{2}] = 5 (2 x - 3) (2 x + 3)$

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Similar questions

Q. Factorize

5 - 20 x^{2}

Q. Factorize :

20 x^{2} + 3 x - 56

Q. Factorise:
20x²– 45

Factorize each of the following polynomials:

(i) x³ + 13x² + 31x − 45 given that x + 9 is a factor

(ii) 4x³ + 20x² + 33x + 18 given that 2x + 3 is a factor.

Q. Use the Factor Theorem to determine whether

g (x)

is factor of

f (x)

in the following case:

f (x) = 4 x^{3} + 20 x^{2} + 33 x + 18, g (x) = 2 x + 3

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Factorize: 20x2 − 45

20x2-45=54x2-9 =52x2-32 =52x-32x+3

Factorize:
20x² − 45

$20 x^{2} - 45 = 5 (4 x^{2} - 9) = 5 [{(2 x)}^{2} - {(3)}^{2}] = 5 (2 x - 3) (2 x + 3)$