wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Factorize: 24a3+37a25a

A
(a+1)(8a1)(3a+5)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
a(8a1)(3a+5)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
(8a1)(3a+5)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
a(8a+1)(3a5)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B a(8a1)(3a+5)
24a3+37a25a
a[24a2+37a5]
a[24a23a+40a5]
a[3a(8a1)+5(8a1)]
a(8a1)(3a+5)

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Method of Identities
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon