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Question

Factorize: 24a3+37a25a

A
(a+1)(8a1)(3a+5)
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B
a(8a1)(3a+5)
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C
(8a1)(3a+5)
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D
a(8a+1)(3a5)
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Solution

The correct option is B a(8a1)(3a+5)
24a3+37a25a
a[24a2+37a5]
a[24a23a+40a5]
a[3a(8a1)+5(8a1)]
a(8a1)(3a+5)

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