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Question

Factorize 27x3y3z39xyz

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Solution

27x3y3z39xyz=(3x)3+(y)3+(z)3×3x×(y)(z)=(3xyz)[(3x)2+(y)2+(z)23x×(y)(y)(z)(z×3x)]=(3xyz)(9x2+y2+z2+3xyyz+3zx)


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