The correct option is B 2(x 4)(x+1) 2x^2 6x 8 ⇒ 2(x^2 3x 4) ⇒ 2(x^2 4x+x 4) ⇒ 2(x(x 4)+1(x 4)) ⇒ 2(x 4)(x+1) ...

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Factorisation Using Algebraic Identities

Factorize 2...

Question

Factorize $2 x^{2} - 6 x - 8$ .

2 (x - 4) (x + 1)

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3 (x + 4) (x - 1)

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2 (x - 3) (x + 2)

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3 (x - 4) (x - 2)

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Solution

The correct option is B $2 (x - 4) (x + 1)$
$2 x^{2} - 6 x - 8$
$\Rightarrow 2 (x^{2} - 3 x - 4)$
$\Rightarrow 2 (x^{2} - 4 x + x - 4)$
$\Rightarrow 2 (x (x - 4) + 1 (x - 4))$
$\Rightarrow 2 (x - 4) (x + 1)$

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(vii) ;

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