Factorize 2 x 2-7 x -5-0A- x-2x-7-5-0B- 2 x-5x-1-0C- 2 x-7x-1-0D- x-2x-7-2-0

The correct option is B We need to find two numbers whose product is (5 × 2) = 10 and whose sum is 7 Let us first split the middle term 7x as 5x 2x [bec ...

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Standard IX

Mathematics

Factorisation of Quadratic Polynomials - Factor Theorem

Factorize 2 x...

Question

Factorize $2 x^{2} - 7 x + 5 = 0$

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Solution

The correct option is B

We need to find two numbers whose product is $(5 \times 2) = 10$ and whose sum is -7

Let us first split the middle term - 7x as -5x -2x [because (-5x) × (-2x) =
$10 x^{2} = (2 x^{2}) \times 5]$ .
So, $2 x^{2} - 7 x + 5 = 2 x^{2} - 5 x - 2 x + 5 = x (2 x - 5) - 1 (2 x - 5) = (2 x - 5) (x - 1)$

Now, $2 x^{2} - 7 x + 5 = 0$ can be rewritten as (2x - 5)(x - 1)= 0.

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Factorize 2x2−7x+5=0

Factorize $2 x^{2} - 7 x + 5 = 0$