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Question

Factorize: (2x+3y)212x18y7

A
(2x+3y+1)(2x+3y7)
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B
(2x+3y+1)(2x+3y+7)
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C
(2x+3y1)(2x+3y7)
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D
(2x+3y1)(2x+3y+7)
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Solution

The correct option is A (2x+3y+1)(2x+3y7)
(2x+3y)212x18y7
(2x+3y)26(2x+3y)7
Let (2x+3y)=a
a26a7
a2+a7a7
a(a+1)7(a+1)
(a+1)(a7)
Substituting a=(2x+3y)
(2x+3y+1)(2x+3y7)

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