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Question

Factorize
(2x+3y)3(2x3y)3

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Solution

(a+b)3(ab)3
=a3+b3+3a2b+3ab2(a3b33a2b+3ab2)
=2b3+6a2b
=2b(b2+3a2)
Thus (2x+3y)3(2x3y)3=3y((3y)2+3(2x)2)=3y(9y2+12x2)
=9y(3y2+4x2)

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