MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

By Grouping

Factorize 2 x...

Question

Factorize

(2x+y)³+(z-y)³-(z+2x)³

Open in App

Solution

2x+y)3+(z−y)3−(z+2x)3
Distribute:
=8x3+12x2y+6xy2+y3+−y3+3y2z+−3yz2+z3+−8x3+−12x2z+−6xz2+−z3

Combine Like Terms:
=8x3+12x2y+6xy2+y3+−y3+3y2z+−3yz2+z3+−8x3+−12x2z+−6xz2+−z3

=(8x3+−8x3)+(12x2y)+(−12x2z)+(6xy2)+(−6xz2)+(y3+−y3)+(3y2z)+(−3yz2)+(z3+−z3)

=12x2y+−12x2z+6xy2+−6xz2+3y2z+−3yz2

Answer:
=12x2y−12x2z+6xy2−6xz2+3y2z−3yz2

Suggest Corrections

thumbs-up

0

Similar questions

{(x + y)}^{3} + {(y + z)}^{3} + {(z + x)}^{3} - 3 (x + y) (y + z) (z + x) = 2 (x^{3} + y^{3} + z^{3} - 3 x y z)

2 (x^{3} + y^{3} + z^{3} - 3 x y z) - (x + y + z) [(x - y)^{2} + (y - z)^{2} + (z - x)^{2}]

(x - y)^{3} + (y - z)^{3} + (z - x)^{3}

x^{3} + y^{3} + z^{3} - 3 x y z = \frac{1}{2} (x + y + z) [(x - y)^{2} + (y - z) + (z - x)^{2}]

Q. X3+y3+z3-3xyz=1/2(x+y+z)[(x-y)2+(y-z)2+(z-x)2.prove

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Grouping

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Standard IX Mathematics

Join BYJU'S Learning Program

CrossIcon