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Question
Factorize :3−a(4+7a)
3−a(4+7a)
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Solution
The correct option is D (3−7a)(1+a)
3−a(4+7a)
=3−4a−7a2
=−7a2−4a+3
=−7a2−7a+3a+3
=−7a(a+1)+3(a+1)
=(a+1)(3−7a)
3−a(4+7a)
=3−4a−7a2
=−7a2−4a+3
=−7a2−7a+3a+3
=−7a(a+1)+3(a+1)
=(a+1)(3−7a)
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