MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Algebraic Identities

Factorize 32a...

Question

Factorize $32 a^{3} + 108 b^{3}$

Open in App

Solution

$32 a^{3} + 108 b^{3} = 4 (8 a^{3} + 27 b^{3}) = 4 [(2 a)^{3} + (3 b)^{3}] = 4 (2 a + 3 b) [(2 a)^{2} - 2 a \times 3 b + (3 b)^{2}] = 4 (2 a + 3 n) (4 a^{2} - 6 a b + 9 b^{2})$

Suggest Corrections

thumbs-up

55

Similar questions

Q. 32a³ + 108b³

Q. The area bounded by the lines y = 2, x = 1, x = a and the curve y = f(x), which cuts the last two lines above the first line for all

a \geq 1

\frac{2}{3} ((2 a)^{3 / 2} - 3 a + 3 - 2 \sqrt{2})

Q. Q) Factorize x⁴ + x
Q) Factorize (m+2n)² + 101(m+2n) + 100

3 a^{2} - 9 a b

by taking common factors.

2 x^{2} - 5 x y + 3 y^{2}

and use your result to factorize

2 {(3 a - b)}^{2} - 5 (3 a - b) (2 a - b) + 3 {(2 a - b)}^{2}

. The factors are

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Algebraic Identities

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Algebraic Identities

Standard IX Mathematics

Join BYJU'S Learning Program

CrossIcon