Factorize :
$3 a^{2} - 1 - 2 a$

(a - 1) (3 a - 1)

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(2 a - 1) (a + 5)

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(a - 1) (3 a + 1)

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(3 a - 2) (a + 1)

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Solution

The correct option is D $(a - 1) (3 a + 1)$
$3 a^{2} - 1 - 2 a$
$= 3 a^{2} - 2 a - 1$
$= 3 a^{2} - 3 a + a - 1$
$= 3 a (a - 1) + (a - 1)$
$= (a - 1) (3 a + 1)$

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