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Question

Factorize: 3a29ab

A
3a(3a3b)
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B
3a(a3b)
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C
3b(3a3)
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D
3a(a9b)
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Solution

The correct option is B 3a(a3b)
3a29ab

Taking out '3a' as common term, we get

3a(3a23a9ab3a)

3a(a3b)

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