1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# Factorize 3x2âˆ’27

A
3(x+3)(x+3)
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
B
3(x3)(x3)
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
C
(x+3)(x3)
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
D
3(x+3)(x3)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

## The correct option is D 3(x+3)(x−3)Given a polynomial expression 3x2−27 Step 1:–––––––– Taking 3 common from the polynomial expression 3x2−27: 3x2−27=3(x2−9) Step 2:–––––––– x2 and 9 are the perfect squares of x and 3 respectively. Also, the terms in the bracket are of the form a2−b2. 3(x2−9)=3(x+3)(x−3) (∵a2−b2=(a+b)(a−b)) The factorization of the polynomial 3x2−27 is 3(x+3)(x−3). Therefore, option (d.) is the correct answer.

Suggest Corrections
1
Join BYJU'S Learning Program
Related Videos
Factorizing of Polynomials
MATHEMATICS
Watch in App
Join BYJU'S Learning Program