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Question

Factorize 3x227

A
3(x+3)(x+3)
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B
3(x3)(x3)
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C
(x+3)(x3)
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D
3(x+3)(x3)
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Solution

The correct option is D 3(x+3)(x3)
Given a polynomial expression 3x227

Step 1:––––––

Taking 3 common from the polynomial expression 3x227:
3x227=3(x29)


Step 2:––––––

x2 and 9 are the perfect squares of x and 3 respectively. Also, the terms in the bracket are of the form a2b2.

3(x29)=3(x+3)(x3) (a2b2=(a+b)(ab))

The factorization of the polynomial 3x227 is 3(x+3)(x3).
Therefore, option (d.) is the correct answer.

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