Factorize 3x2−(3√3−1)x−√3 and verify relationship between the zeroes and the coefficients. [2 MARKS]
Factorisation : 1 Mark
Verification : 1 Mark
Given polynomial is,
3x2−(3√3−1)x−√3
=3x2−3√3x+x−√3
=3x(x−√3)+1(x−√3)
=(x−√3)(3x+1)
So the zeroes are,
x−√3=0⇒x=√3
3x+1=0⇒x=−13
For verification,
α+β=−13+√3=3√3−13=−ba
αβ=−13×√3=−1√3=ca