We have: 4a+b 6a+b2=2a+b2 3a+b nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; =2a+b2 3a 3b ...

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Algebraic Identities

Factorize:4a+...

Question

Factorize:
4(a + b) − 6(a + b)²

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Solution

We have:
$4 (a + b) - 6 {(a + b)}^{2} = 2 (a + b) [2 - 3 (a + b)]$
$= 2 (a + b) (2 - 3 a - 3 b)$

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Similar questions

Factorise:
$4 (a + b) - 6 (a + b)^{2}$

factorize 4(a+b)-6(a+b)^2

(2 a + b)^{2} - 6 a - 3 b - 4

(2 a + b)^{2} - 6 a - 3 b - 4

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