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B
(4x−y−3)(ax−y−1)
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C
(x−6y−3)(2x−y+1)
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D
(4x−6y−3)(4x−6y+1)
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Solution
The correct option is D(4x−6y−3)(4x−6y+1) 4(2x−3y)2−8x+12y−3 =4(2x−3y)2−4(2x−3y)−3 Let (2x−3y) be a Therefore, =4a2−4a−3 =4a2−6a+2a−3 =2a(2a−3)+1(2a−3) =(2a+1)(2a−3) Putting the value of a we get, =[2(2x−3y)+1][2(2x−3y)−3] =(4x−6y+1)(4x−6y−3)