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Question

Factorize :
4(2x3y)28x+12y3

A
(4x6y3)(2x6y1)
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B
(4xy3)(axy1)
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C
(x6y3)(2xy+1)
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D
(4x6y3)(4x6y+1)
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Solution

The correct option is D (4x6y3)(4x6y+1)
4(2x3y)28x+12y3
=4(2x3y)24(2x3y)3
Let (2x3y) be a
Therefore,
=4a24a3
=4a26a+2a3
=2a(2a3)+1(2a3)
=(2a+1)(2a3)
Putting the value of a we get,
=[2(2x3y)+1][2(2x3y)3]
=(4x6y+1)(4x6y3)

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