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Byju's Answer
Standard VIII
Mathematics
Factorisation by common factors
Factorize: 4...
Question
Factorize:
4
x
2
−
12
a
x
−
y
2
−
z
2
−
2
y
z
+
9
a
2
.
A
(
2
x
−
3
a
+
y
+
z
)
(
2
x
−
a
−
y
+
z
)
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B
(
2
x
−
3
a
+
y
−
z
)
(
2
x
−
3
a
−
y
−
z
)
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C
(
2
x
−
3
a
+
y
+
z
)
(
2
x
−
3
a
−
y
−
z
)
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D
(
x
−
3
a
+
y
+
z
)
(
2
x
−
3
a
−
y
−
z
)
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Solution
The correct option is
C
(
2
x
−
3
a
+
y
+
z
)
(
2
x
−
3
a
−
y
−
z
)
4
x
2
−
12
a
x
−
y
2
−
z
2
−
2
y
z
+
9
a
2
=
4
x
2
−
12
a
x
+
9
a
2
−
y
2
−
z
2
−
2
y
z
=
(
2
x
)
2
−
2
(
2
x
)
(
3
a
)
+
(
3
a
)
2
−
(
y
2
+
2
y
z
+
z
2
)
[Using
(
a
+
b
)
2
=
a
2
+
2
a
b
+
b
2
]
=
(
2
x
−
3
a
)
2
−
(
y
+
z
)
2
[Using
a
2
−
b
2
=
(
a
+
b
)
(
a
−
b
)
]
=
(
2
x
−
3
a
+
y
+
z
)
(
2
x
−
3
a
−
y
−
z
)
Suggest Corrections
0
Similar questions
Q.
If x=6a+8b+9c;y=2b-3a-6c and z=c-b+3a ; find
(i) x+y+z (ii) x-y+z
(iii) 2x-y-3z (iv) 3y-2z-5x
Q.
State True or False:
If
x
=
6
a
+
8
b
+
9
c
;
y
=
2
b
−
3
a
−
6
c
and
z
=
c
−
b
+
3
a
; then
2
x
−
y
−
3
z
is
6
a
+
17
b
+
21
c
.
Q.
If
x
=
log
2
a
a
,
y
=
log
3
a
2
a
,
z
=
log
4
a
3
a
, prove that
1
+
x
y
z
=
2
y
z
.
Q.
Factorise
x
2
(
y
−
z
)
+
y
2
(
z
−
x
)
+
z
2
(
x
−
y
)
Q.
Assertion :
tan
3
A
−
tan
2
A
−
tan
A
=
tan
3
A
tan
2
A
tan
A
Reason: If
x
=
y
+
z
,then
tan
x
−
tan
y
−
tan
z
=
tan
x
tan
y
tan
z
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