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Question

Factorize:
4x2−12ax−y2−z2−2yz+9a2.

A
(2x3a+y+z)(2xay+z)
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B
(2x3a+yz)(2x3ayz)
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C
(2x3a+y+z)(2x3ayz)
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D
(x3a+y+z)(2x3ayz)
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Solution

The correct option is C (2x3a+y+z)(2x3ayz)
4x212axy2z22yz+9a2
=4x212ax+9a2y2z22yz
=(2x)22(2x)(3a)+(3a)2(y2+2yz+z2) [Using (a+b)2=a2+2ab+b2]
=(2x3a)2(y+z)2 [Using a2b2=(a+b)(ab)]
=(2x3a+y+z)(2x3ayz)

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