Factorize:
5√5x2+20x+3√5
5√5x2+20x+3√5=5√5x2+5x+15x+3√5⎧⎪⎨⎪⎩∵5√5×3√5=75∴75=15×520=15+5⎫⎪⎬⎪⎭=√5x(5x+√5)+3(5x+√5)=(5x+√5)(√5x+3)
Factorize √5 x2 + 8x + 3√5 = 0 into the form √5 x2 + px + qx +3√5 = 0.Find the value of p and q.
Factorize √5x2+8x+3√5=0 into the form √5x2+px+qx+3√5=0. What is the value of p2+q2 ?
If (x+5) is a factor of p(x)=x3−20x+5k then k=? (a) -5 (b) 5 (c) 3 (d)-3