The correct option is
A yz(5xz−3)We know that
a(b+c)=ab+ac and the reverse process
ab+ac=a(b+c) is called taking out the common factor.
Consider the factorization of the expression 5xyz2−3zy:
5xyz2=5×x×y×z×z3zy=3×z×y
⇒HCF(5xyz2,3zy)=z×y=yz
Therefore, we have:
5xyz2−3zy=(5×x×y×z×z)−(3×z×y)=yz(5xz−3)
Hence, 5xyz2−3zy=yz(5xz−3).