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Question

Factorize 5xyz2−3zy

A
yz(5xz3)
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B
yz(5yz3)
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C
xz(5xz3y)
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D
None of these
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Solution

The correct option is A yz(5xz3)
We know that a(b+c)=ab+ac and the reverse process ab+ac=a(b+c) is called taking out the common factor.

Consider the factorization of the expression 5xyz23zy:

5xyz2=5×x×y×z×z3zy=3×z×y

HCF(5xyz2,3zy)=z×y=yz

Therefore, we have:

5xyz23zy=(5×x×y×z×z)(3×z×y)=yz(5xz3)

Hence, 5xyz23zy=yz(5xz3).

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