Factorize $64 a^{3}$ $- 27 b^{3}$ $- 144 a^{2} b$ $+ 108 a b^{2}$

Open in App

Solution

$= 64 a^{3} - 27 b^{3} - 144 a^{2} b + 108 a b^{2}$
$= {(4 a)}^{3} - (3 b)^{3} - 4 a \times 4 a \times 3 \times 3 b + 4 a \times {(3 b)}^{2} \times 3$
$= {(4 a - 3 b)}^{3}$

Suggest Corrections

Similar questions

64 a^{3} - 27 b^{3} - 144 a^{2} b + 108 a b^{2}

Factorise each of the following: 64 $a^{3}$ – 27 $b^{3}$ – 144 $a^{2}$ b + 108a $b^{2}$

64 a^{3} - 27 b^{3} - 144 a^{2} b + 108 a b^{2}

64 a^{3} - 27 b^{3} - 144 a^{2} b + 108 a b^{2}

64 a^{3} - 27 b^{3} - 144 a^{2} b + 108 a b^{2}

= (4 a - 3 b) (4 a - 3 b) (4 a - 3 b)

Join BYJU'S Learning Program