64a^3 b^3 = (4a)^3 (b)^3 = (4a b ) [(4a)^2 + 4a × b + (b)^2] = (4a b) (16a^2 + 4ab + b^2) ...

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Algebraic Identities

Factorize: 64...

Question

Factorize:

$64 a^{3} - b^{3}$

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Solution

$64 a^{3} - b^{3} = (4 a)^{3} - (b)^{3} = (4 a - b) [(4 a)^{2} + 4 a \times b + (b)^{2}] = (4 a - b) (16 a^{2} + 4 a b + b^{2})$

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Similar questions

Factorize $64 a^{3} - 343 b^{3}$

64 a^{3}

- 27 b^{3}

- 144 a^{2} b

+ 108 a b^{2}

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