Factorize : $6 a^{2} - a - 15$

(3 a + 5) (a^{2} + 3)

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(3 a - 5) (2 a + 3)

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(3 a + 5) (a + 3)

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(a - 5) (a + 3)

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Solution

The correct option is C $(3 a - 5) (2 a + 3)$
$6 a^{2} - a - 15$
$= 6 a^{2} - 10 a + 9 a - 15$
$= 6 a^{2} + 9 a - 10 a - 15$
$= 3 a (2 a + 3) - 5 (2 a + 3)$
$= (2 a + 3) (3 a - 5)$

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