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Question

Factorize 9x212axy2z22yz+4a2.

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Solution

We factorize the given expression 9x212axy2z22yz+4a2 as shown below:

9x212axy2z22yz+4a2=(9x212ax+4a2)(y2+z2+2yz)=[(3x)2(2×3x×2a)+(2a)2](y+z)2((a+b)2=a2+b2+2ab)=(3x2a)2(y+z)2((ab)2=a2+b22ab)=(3x2a+y+z)(3x2ayz)(a2b2=(a+b)(ab))

Hence, 9x212axy2z22yz+4a2=(3x2a+y+z)(3x2ayz).

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