Question

Factorize 98$(a+b{)}^2-2$

• A. 2($7a+7b+1\left)\right(7a+7b-1)$
• B. 2($7a+7b+1)$
• C. 98($a+b+1\left)\right(a+b-1)$
• D. ($a+b+1\left)\right(a+b-1)$ - 2

Answer 1

The correct option is A

2($7a+7b+1\left)\right(7a+7b-1)$

Given $98(a+b{)}^2-2$
$=2\left(49\right(a+b{)}^2)-1)$
$=2\left(\right(7(a+b){)}^2-1)$
$=2(7a+7b+1)(7a+7b-1)$