Factorize $9 x^{2} - 16 y^{2}$ for $x = 2, y = 1$ .

Open in App

Solution

$9 x^{2} - 16 y^{2} = (3 x)^{2} - (4 y)^{2}$
$\Rightarrow (3 x + 4 y) (3 x - 4 y)$
for $x = 2, y = 1$
$(6 + 4) (6 - 4) = 20$

Suggest Corrections

Similar questions

Factorize: $9 x^{2} + 16 y^{2} + 4 z^{2} - 24 x y + 16 y z - 12 x z$

9 x^{2} - 24 x y + 16 y^{2}

p (x) = 9 x^{2} + y^{2} + 4 z^{2} + 6 x y - 4 y z - 12 x z

P (x)

x = 1, y = 1, z = 1

x = 1 + 4 cos θ, y = 2 + 3 sin θ, θ \in R,

y = x + k

9 x^{2} - 16 y^{2} = 144

k =

Join BYJU'S Learning Program