Factorize: $a^{2}$ +2ab + $b^{2}$ - $c^{2}$

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Solution

Solution:
$a^{2}$ +2ab + $b^{2}$ - $c^{2}$
= $(a + b)^{2}$ - $c^{2}$
= (a + b + c)(a + b - c) ..... Using identity

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Similar questions

If a + b + c = 2s, then prove the following identities

(a) s² + (s − a)² + (s − b)² + (s − c)² = a² + b² + c²

(b) a² + b² − c² + 2ab = 4s (s − c)

(d) a² − b² − c² + 2ab = 4(s − b) (s − c)

(e) (2bc + a² − b² − c²) (2bc − a² + b² + c²) = 16s (s − a) (s − b) (s − c)

(f)

$a^{2} + b^{2} - c^{2} - d^{2} + 2 a b - 2 c d$ .

a^{2} + b^{2} - c^{2} - d^{2} + 2 a b - 2 c d

a^{2} - 2 a b + b^{2} - c^{2}

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