CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Factorize:

a2b2+2bcc2

Open in App
Solution

a2b2+2bcc2=a2(b22bc+c2){a2+b22ab=(ab)2}=a2(bc)2=(a)2(bc)2{a2b2=(a+b)(ab)}=(a+bc)(ab+c)


flag
Suggest Corrections
thumbs-up
2
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Algebraic Identities
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon