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Question

Factorize:
(a2b2)(x2y2)+4abxy.

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Solution

Now,
(a2b2)(x2y2)+4abxy
=a2x2+b2y2+2abxy(a2y22abxy+b2x2)
=(ax+by)2(aybx)2
=(ax+by+aybx)(ax+byay+bx).

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