Factorize :
$a^{3} - 27 b^{3} + 2 a^{2} b - 6 a b^{2}$

(a - 3 b) (a^{2} + 5 a b + 9 a^{2})

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(a - b) (a^{2} + 5 b + 9 a^{2})

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(a - 3 b) (a^{2} + 5 a b + 9 b^{2})

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(a - b) (a^{2} + 5 a + 9 b^{2})

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Solution

The correct option is B $(a - 3 b) (a^{2} + 5 a b + 9 b^{2})$
$a^{3} - 27 b^{3} + 2 a^{2} b - 6 a b^{2}$
$= (a)^{3} - (3 b)^{3} + 2 a b (a - b)$
$= (a - 3 b) (a^{2} + a (3 b) + (3 b)^{2}) + 2 a b (a - 3 b)$
$= (a - 3 b) (a^{2} + 3 a b + 9 b^{2} + 2 a b)$
$= (a - 3 b) (a^{2} + 5 a b + 9 b^{2})$

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Similar questions

a^{3} - 27 b^{3} + 2 a^{2} b - 6 a b^{2}

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