Factorize- a 3- a -3 a 2-3A- a 2-1 a -3B- a -1 a -3- a 2-1 a 2-3D- a -1 a -32

The correct option is A (a^2 + 1)(a 3)⇒ a^3 + a 3a^2 3 ⇒ a(a^2 + 1) 3(a^2 + 1) Taking out (a^2 + 1) common, we get, ⇒ (a^2 + 1)(a 3) ...

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Taking Out Common Factors

Factorize: a ...

Question

Factorize: $a^{3} + a - 3 a^{2} - 3$

(a^{2} + 1) (a - 3)

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(a + 1) (a - 3)

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(a + 1) (a - 3)^{2}

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(a^{2} + 1) (a^{2} + 3)

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3 a^{2} - 1 - 2 a

a + \frac{1}{a} = - 2, then a^{2} + \frac{1}{a^{2}} =_________.

∣ ∣ ∣ ∣ ∣ \begin{matrix} (a - a_{1})^{- 2} & (a - a_{1})^{- 1} & a_{1}^{- 1} (a - a_{2})^{- 2} & (a - a_{2})^{- 1} & a_{2}^{- 1} (a - a_{3})^{- 2} & (a - a_{3})^{- 1} & a_{3}^{- 1} \end{matrix} ∣ ∣ ∣ ∣ ∣ = \pm \frac{a^{2} \prod (a_{i} - a_{j})}{\prod a_{i} \prod (a - a_{i})^{2}}

a^{2} + \frac{1}{a^{2}} = 102

a - \frac{1}{a}

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