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Factorisation Using Algebraic Identities

Factorize a5b...

Question

Factorize $a^{5} b - a b^{5}$ .

(a - b) (a^{2} + b^{2})

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a b (a^{2} + b^{2})

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a b (a^{2} + b^{2}) (a + b) (a - b)

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(a + b) (a - b)

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Solution

The correct option is C $a b (a^{2} + b^{2}) (a + b) (a - b)$
$a b (a^{2} + b^{2}) (a + b) (a - b)$

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Similar questions

{(\frac{4}{11})}^{6} = \frac{4^{}}{11^{}}

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{(\frac{1}{10})}^{20} = \frac{1}{10^{}}

{(\frac{a}{b})}^{2} = \frac{a^{}}{b^{}}

{(\frac{6}{7})}^{3} = \frac{6^{}}{7^{}}

{(\frac{5}{7})}^{8} = \frac{5^{}}{7^{}}

{(\frac{x}{y})}^{7} = \frac{x^{}}{y^{}}

{(\frac{1}{5})}^{3} = \frac{1^{}}{5^{}}

a * b = \frac{a b}{5} for all a, b \in R - \{0\}

a * b = \frac{a b}{5} for all a, b \in Q_{0}

a^{5} b - a b^{5}

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