Factorize:
$a (a - 1) - b (b - 1)$

(a - b) (a + b - 1)

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(a + b) (a + b - 1)

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(2 a - b) (a - b - 1)

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(2 a + b) (a + b + 1)

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Solution

The correct option is A $(a - b) (a + b - 1)$
$a (a - 1) - b (b - 1)$
$= a^{2} - a - b^{2} + b$
$= a^{2} - b^{2} - a + b$
$= (a + b) (a - b) - 1 (a - b)$
$= (a - b) (a + b - 1)$

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Similar questions

t a n (\frac{π}{4} + \frac{1}{2} c o s^{- 1} \frac{a}{b}) + t a n (\frac{π}{4} - \frac{1}{2} c o s^{- 1} \frac{a}{b})

Factors of $a^{2} - b + a b - a$ are

a = - 1

b = 2,

\frac{a^{b} \times b^{a}}{b - 2 a}

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