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Question

Factorize (13y2−47y+5)−(27y−23y2+2)−(17y−3+2y2)

A
(y2)(y+3)
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B
(y2)(y3)
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C
(y+2)(y+3)
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D
(y+2)(y3)
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Solution

The correct option is C (y2)(y+3)
(13y247y+5)(27y23y2+2)(17y3+2y2)=0
y2(13+232)+y(472717)+(52+3)=0
y2(12)+y(1)+6=0
y2y+6=0
y2+y6=0
y2+3y2y6=0
y(y+3)2(y+3)=0
(y2)(y+3)=0

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