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Question

Factorize :
2(ab+cd)a2b2+c2+d2

A
(c+dab)(cda+b)
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B
(c+db)(c+dab)
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C
(c+d+ab)(c+da+b)
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D
(c+d+a)(c+d+a+b)
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Solution

The correct option is C (c+d+ab)(c+da+b)
2(ab+cd)a2b2+c2+d2
=2ab+2cda2b2+c2+d2
=c2+d2+2cd(a2+b22ab)
=(c+d)2(ab)2
=(c+d+ab)(c+da+b)

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