Factorize - x2 - a2 - 1-ax - 1

The correct option is C (x + 1/a) (x + a) #160; x^2 + a^2 + 1ax + 1 =x^2 + ax + #160;xa + 1 =x^2 #160;+ #160;xa+ ax #160;+ 1 ...

You visited us 4 times! Enjoying our articles? Unlock Full Access!

By Grouping

Factorize : ...

Question

Factorize : $x^{2} + \frac{a^{2} + 1}{a} x + 1$

(2 x + \frac{1}{a}) (x - a)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(x + \frac{1}{a}) (x + a)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

(5 x + \frac{1}{a}) (x - a)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(7 x + \frac{1}{a}) (x + a)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

x^{2} + \frac{a^{2} + 1}{a} x + 1

x^{2} + \frac{a^{2} - 1}{a} x - 1

{tan}^{- 1} {\frac{\sqrt{1 + a^{2} x^{2}} - 1}{a x}}

x .

(x) = ⎧ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎩ \begin{matrix} \frac{1 - a^{x} + x a^{x} {log}_{e} a}{a^{x} x^{2}}, x < 0 \frac{2^{x} a^{x} - x {log}_{e} 2 - x {log}_{e} a - 1}{x^{2}}, x < 0 \end{matrix}, a > 0

x = 0

l i m x \to a \frac{\sqrt{1 + a x} - \sqrt{1 - a x}}{x}

Join BYJU'S Learning Program