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Question

Factorize each of the following algebraic expression:
a4 + 3a2 +4

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Solution

a4+3a2+4=a4+4a2-a2+4=(a4+4a2+4)-a2=[(a2)2+2×a2×2+22]-a2=(a2+2)2-a2=[(a2+2)-a][(a2+2)+a]=(a2-a+2)((a2+a+2)

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