Question

Factorize the following expression:​ $16(2x-1{)}^2-25y^2$

Answer 1

We have, $16(2x-1{)}^2-25y^2$

$=\left[4\right(2x-1){]}^2-(5y{)}^2$

$=\left[4\right(2x-1)-5y]\left[4\right(2x-1)+5y]$ [$\because (a^2-b^2)=(a-b)(a+b)$]

$=(8x-4-5y)(8x-4+5y)$

$=(8x-5y-4)(8x+5y-4)$