Question

Factorize each of the following expressions:

$3a^5-48a^3$

Answer 1

Given: $3a^5-48a^3$

$\therefore 3a^5-48a^3$
$=3a^3(a^2-16)$
$=3a^3(a^2-4^2)$
$=3a^3(a+4)(a-4)[\because a^2-b^2=(a+b\left)\right(a-b\left)\right]$

Hence, $3a^5-48a^3=3a^3(a+4)(a-4)$.