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Question

Factorize each of the following expressions:

a416b4

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Solution

Given: a416b4

a416b4
=(a2)2(4b2)2
=(a24b2)(a2+4b2) [a2b2=(a+b)(ab)]
=[a2(2b)2] (a2+4b2)
=(a+2b)(a2b)(a2+4b2)

Hence, a416b4=(a2b)(a+2b)(a2+4b2).


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